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Senin, 01 Agustus 2011

Soal dan Jawaban LimiT

LIMIT
lim┬(x→0)⁡〖〖(7x^2+sin⁡〖(2x^2)〗)/(〖tan 〗^2 3x)〗^ 〗 = …
Answer :
lim┬(x→0)⁡〖〖((√(7 x)))/〖〖(tan 〗^2 3x)〗^2 〗^2 〗 + sin⁡〖〖(√2)〗^2 〗/〖(tan⁡3x)〗^2 = 7/9+2/9 = 1
(_x→3^Lim) (9- x^2)/(4- √(x^2+7)) = …

Answer :

(_x→3^Lim) (9- x^2)/(4- √(x^2+7)) = (_x→3^Lim) ((4 - √(x^2+7 )))/(4- √(x^2+7)) ((4 - √(x^2+7 )))/ = 4 + 4 = 8

(_x→∞^Lim) ((4+5x)(2-x))/((2+x)(1-x))=⋯

Answer :
(_x→∞^Lim) (– 5 x^2)/〖- x〗^2 =5
(_x→∞^Lim) √(x^2+ x+5) - √(x^2+ 2x+3) = …

Answer :

(_x→∞^Lim) √(〖ax〗^2+ bx+c) - √(〖ax〗^2+ px+q) = (b-q)/(2√a)
(_x→∞^Lim) √(x^2+ x+5) - √(x^2+ 2x+3) = (1+2 )/(2√1)=3/2

(_t→2^Lim) (t^3- 8)/(t^2+ t-6) = …
Answer :
(_t→2^Lim) (3t^2)/(2t + 1) = 12/5

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